Make customizable worksheets about constant (or average) speed, time, and distance for pre-algebra and algebra 1 courses (grades 6-9). Both PDF and html formats are available. You can choose the types of word problems in the worksheet, the number of problems, metric or customary units, the way time is expressed (hours/minutes, fractional hours, or decimal hours), and the amount of workspace for each problem.
Distance, rate and time problems are a standard application of linear equations. When solving these problems, use the relationship rate (speed or velocity) times time equals distance.
time distance speed problems pdf 11
The third column, distance, will always be filled in by multiplying the rate and time columns together. If given a total distance of both persons or trips, put this information in the distance column. Now use this table to set up and solve the following examples.
Nick and Chloe left their campsite by canoe and paddled downstream at an average speed of 12 km/h. They turned around and paddled back upstream at an average rate of 4 km/h. The total trip took 1 hour. After how much time did the campers turn around downstream?
Distance, time and rate problems have a few variations that mix the unknowns between distance, rate and time. They generally involve solving a problem that uses the combined distance travelled to equal some distance or a problem in which the distances travelled by both parties is the same. These distance, rate and time problems will be revisited later on in this textbook where quadratic solutions are required to solve them.
Let us take a look at some simple examples of distance, time and speed problems. Example 1. A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km?
Speed = Distance/time = 15/2 = 7.5 miles per hour. Example 3. A car takes 4 hours to cover a distance, if it travels at a speed of 40 mph. What should be its speed to cover the same distance in 1.5 hours?
So, he covered a distance of 6 miles in 1.5 hours. Example 5. A train is going at 1/3 of its usual speed and it takes an extra 30 minutes to reach its destination. Find its usual time to cover the same distance.
Example 1. A boy travelled by train which moved at the speed of 30 mph. He then boarded a bus which moved at the speed of 40 mph and reached his destination. The entire distance covered was 100 miles and the entire duration of the journey was 3 hours. Find the distance he travelled by bus.
Solving which gives d = 60, which is the distance travelled by train. 100-60 = 40 miles is the distance travelled by bus. Example 2. A plane covered a distance of 630 miles in 6 hours. For the first part of the trip, the average speed was 100 mph and for the second part of the trip, the average speed was 110 mph. what is the time it flew at each speed?
Meera walked to school at a speed of 3 miles per hour. Once she reached the school, sherealized that she forgot to bring her books, so rushed back home at a speed of 6 miles perhour. She then walked back to school at a speed of 4 miles per hour. All the times, shewalked in the same route.please explain above problem
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 KMS away from A at the same time. On the way, however the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
A cyclist completes a distance of 60 km at the same speed throughout. She travels 10 km in one hour. She stops every 20 km for one hour to have a break. What are the two variables involved in this situation?
2. Find out the distance covered when, speed is 960 km/hour and time is 1 hour 50 minutes. 3. Determine the time taken when, distance is 7150 km and speed is 780 km/hr.
6. The speed of the train is 72 km per hour. Find its speed in metre per second.7. Express the speed of 60 m per minute in km per hour.8. A man runs at the speed of 10 km/hr. How much time will he take to cover 750 metres?9. Aaron ran 500 metre in 100 Seconds. Find the speed in km per hour.10. A cyclist travels at a speed of 20 km/hour. How far will he travels in 50 minutes?
Example:Marie Ann is trying to predict the time required to ride her bike to the nearby beach. Sheknows that the distance is 45 km and, from other trips, that she can usually average about20 km/h. Predict how long the trip will take.
Time is entered in minutes, speed in knots and distance in nautical miles (the same formula will work for statute miles and kilometres). The use of "60" ensures that time is calculated in minutes rather than in hours and tenths of an hour.
Speed distance time is the formula used to explain the relationship between speed, distance and time. That is speed = distance time. Or to put it another way distance divided by speed will give you the time. Provided you know two of the inputs you can work out the third.
This formula can also be rearranged to calculate distance or calculate time given the other two measures. An easy way to remember the formula and the different rearrangements is to use this speed distance time triangle.
When you use the speed distance time formula you must check that each measure is in the appropriate unit before you carry out the calculation. Sometimes you will need to convert a measure into different units. Here are some useful conversions to remember.
When using the speed distance time formula you must ensure that the units of the measures are compatible.For example, if a car travels at 80 \ km per hour for 30 minutes and you are asked to calculate the distance, a common error is to substitute the values straight into the formula and do the following calculation. Distance = speed \times time = 80 \times 30 = 2400 \ km The correct way is to notice that the speed uses hours but the time given is in minutes. Therefore you must change 30 minutes into 0.5 hours and substitute these compatible values into the formula and do the following calculation. Distance = speed \times time = 80 \times 0.5 = 40 \ km
Firstly convert 20 minutes to hours. 20 minutes is a third of an hour or \frac13 hours. \beginaligned&Speed = distance \div time \\\\&Speed =18 \div \frac13 \\\\&Speed = 54 \\\\&54 \ km/h\endaligned 2ff7e9595c
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